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**Here is list of Questions and Answers covering all key area of Pie Chart 2 topic of Pie Chart:**

1. If the population of village R in 1997 is 32000, then what will be the population of village Y below poverty line in that year?

**Answer:** Option
B

**Explanation:**

Population of village R = 32000(given). Let the population of village Y be y.
Then, 16:15 = 32000:y => y = (15 * 32000)/16 = 30000 Population of village Y below poverty line = 52% of 30000 = 15600.

2. Find the population of village S if the population of village X below poverty line in 1997 is 12160.

**Answer:** Option
C

**Explanation:**

Let the population of village X be x.
Then, 38% of x = 12160 => x = (12160 * 100)/38 = 32000 Now, if s be the population of village S, then
16 : 11 = 32000 : s => s = (11 * 32000)/16 = 22000.

3. If in 1998, the population of village Y and V increase by 10% each and the percentage of population below poverty line remains unchanged for all the villages, then find the population of village V below poverty line in 1998, given that the population of village Y in 1997 was 30000.

**Answer:** Option
B

**Explanation:**

Population of village Y in 1997 = 30000(given)
Let the population of village V in 1997 be v.
Then, 15:10 = 30000:v => v = (30000 * 10)/15 = 20000 Now, population of village V in 1998 = 20000 + (10% of 20000) = 22000.
Population of village V below poverty line in 1998 = 58% of 22000 = 12760.

4. If in 1999, the population of village R increased by 10% while that of village Z reduces by 5% compared to that in 1997 and the percentage of population below poverty line remains uncharged for all the villages, then find the approximate ratio of population of village R below poverty line to the ratio of population of village Z below poverty line for the year 1999.

**Answer:** Option
A

**Explanation:**

Let the total population of all the seven villages in 1997 be N.
Then, population of village R in 1997 = 16% of N = 16/100 N
and population of village Z in 1997 = 11% of N = 11/100 N
Population of village R in 1999 = {16/100 N + (10% of 16/100 N)} = 1760/10000 N
and population of village Z in 1999 = {11/100 N - (5% of 11/100 N)} = 1045/10000 N
Now, population of village R below poverty line for 1999 = 51% of (1760/10000 N)
and population of village Z below poverty line for 1999 = 42% of (1045/10

5. The ratio of population of village T below poverty line to that of village Z below poverty line in 1997 is :

**Answer:** Option
C

**Explanation:**

Let N be the total population of all the seven villages. Then, population of village T below poverty line = 46% of (21% of N) and population of village Z below poverty line 42% of (11% of N)
Required ratio = [46% of (21% of N)]/[42% of (11% of N)] = (46 * 21)/(42 * 11) = 23/11.